Pop operators from the stack and append them to the postfix expression as long as the stack is not empty, the top of the stack is not '(', and the operator at the top of the stack has higher or equal precedence than the current operator (for left-associative operators).

Push the current operator onto the stack.

After scanning the entire expression, pop any remaining operators from the stack and append them to the postfix expression.

Precedence (Higher to Lower): $\uparrow$ (Exponentiation) $\rightarrow$ $*, /$ $\rightarrow$ $+, -$

Transformation Steps:

Scanned Symbol	Stack	Postfix Expression
A		A
+	+	A
(	+(	A
B	+(	AB
*	+(*	AB
C	+(*	ABC
-	+(-	ABC*
(	+(-(	ABC*
D	+(-(	ABC*D
/	+(-(/	ABC*D
E	+(-(/	ABC*DE
$\uparrow$	+(-(/$\uparrow$	ABC*DE
F	+(-(/$\uparrow$	ABC*DEF
)	+(-	ABC*DEF$\uparrow$/
*	+(-*	ABC*DEF$\uparrow$/
G	+(-*	ABC*DEF$\uparrow$/G
)	+	ABCDEF$\uparrow$/G -
(End)		ABCDEF$\uparrow$/G-+

Resulting Postfix Expression: $A B C * D E F \uparrow / G * - +$

3. (c) Postfix Expression Evaluation

Postfix Expression: $2, 3, 10, +, *, 8, 2, /,-$
Rules for Postfix Evaluation:
1. Scan the postfix expression from left to right.
2. If an operand is encountered, push it onto the stack.
3. If an operator is encountered, pop the required number of operands (usually two) from the stack, perform the operation, and push the result back onto the stack.
4. After scanning the entire expression, the final result will be the only element left on the stack.

Evaluation Steps:

Scanned Symbol	Stack	Operation/Comment
2	[2]	Push 2
3	[2, 3]	Push 3
10	[2, 3, 10]	Push 10
+	[2, 13]	Pop 10, 3. $3+10=13$. Push 13.
*	[26]	Pop 13, 2. $2*13=26$. Push 26.
8	[26, 8]	Push 8
2	[26, 8, 2]	Push 2
/	[26, 4]	Pop 2, 8. $8/2=4$. Push 4.
-	[22]	Pop 4, 26. $26-4=22$. Push 22.

Result: The final value of the expression is $22$.

4. (a) Stack Overflow in Linked Stack

In a linked list implementation of a stack, new nodes are dynamically allocated from the heap memo